The reaction $A (g) + 2B (g) \to C (g) + D (g)$ is an elementary process. In an experiment involving this reaction, the initial partial pressure of A and B are $p_{A} {= 0.60 atm and p}_{B} = 0.80$ atm respectively. When $p_{C} = 0.20$ atm, the rate of the reaction relative to the initial rate is

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1/36

1/18

1/6

answer is A.

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Detailed Solution

$A (g) + 2B (g) \to C (g) + D (g)$

$Rate = k [A] {[B]}^{2} = k (0.60) {(0.80)}^{2} ........... (i)$

${when p}_{C} {= 0.20 atm p}_{A}$ is reduced to 0.40 and $p_{B} = 0.40$ (See stoichiometric representation)

$Rate = k [0.40] {[0.40]}^{2} ........... (ii)$

$∴ (ii) divide by (i) = \frac{0.40 ×0.40 × 0.40}{0.60 × 0.80 × 0.80} = \frac{1}{6}$

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