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Q.

The reaction A(g) + 2B(g) C(g)+ D(g)is an elementary process. In an experiment   involving this reaction, the initial partial pressure of A and B are pA = 0.60 atm and pB = 0.80  atm respectively. When pC = 0.20atm, the rate of the reaction relative to the initial rate is

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a

1/6

b

1/12

c

1/36

d

1/18

answer is A.

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Detailed Solution

A(g) + 2B(g) C(g) + D(g)

Rate = k[A][B]2 = k(0.60)(0.80)2...........(i)

when pC = 0.20 atm pAis reduced to 0.40 and pB = 0.40(See stoichiometric representation)

Rate = k[0.40][0.40]2...........(ii)

(ii) divide by (i) = 0.40 ×0.40 × 0.400.60 × 0.80 × 0.80  = 16

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