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Q.

The reaction ${Br}_{2} + {CH}_{3} Br \overset{hv}{\to} {CH}_{2} {Br}_{2} + HBr$ was carried out. Which of the following mechanism steps is productive, but relatively unlikely to occur?

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a

$Br ∙ + ∙ {CH}_{3} \to {CH}_{3} Br$

b

$Br ∙ + ∙ {CH}_{2} Br \to {CH}_{2} {Br}_{2}$

c

$Br ∙ + {Br}_{2} \to {Br}_{2} + Br ∙$

d

$Br ∙ + {CH}_{3} Br \to HBr + ∙ {CH}_{2} Br$

answer is A.

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Detailed Solution

Two different free radicals are reacting but they are unlikely to occur.

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