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The reaction v1A+v2Bproducts is first-order with respect to A and zero-order with respect to B. If the reaction is started with [A]0and [B]0, the integrated rate expression of this reaction would be

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a
ln[A]0[A]0x=k1t
b
ln[A]0[A]0v1x=k1t
c
ln[A]0[A]0v1x=v1k1t
d
ln[A]0[A]0v1x=v1k1t
where x is the extent of reaction divided by constant volume.

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detailed solution

Correct option is C

We have 

-1v1d[A]dt=k[ A]   i.e.   [A]][A]d[A][A]=-v1k0l dt

ln[A][A]0=-v1kt   or   ln[A]0[ A]0-v1x=v1kt

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