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The reading of Centigrade thermometer coincides with that of Fahrenheit thermometer in a liquid. The temperature of the liquid is

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0°C

-40°C

100°C

300°C

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{C}{100} = \frac{F - 32}{180} \\ C = F = x \\ \frac{x}{5} = \frac{x - 32}{9} \\ x = - 40^{\circ} \\ ∴ C = F = - 40^{\circ} \\ ∴ t_{c} = - 40^{\circ} c \\ t_{F} = - 40^{\circ} F \end{array}$

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