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The reading of the ideal voltmeter in the adjoining diagram will be

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4 V

8 V

12 V

14 V

answer is B.

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Detailed Solution

Current{\text{ }}flowing{\text{ }}in{\text{ }}the{\text{ }}circuit\,\,i = \frac{E}{R} = \frac{{10 - 4}}{{20 + 10}} = \frac{1}{5}A

P.D.\,acrossAC\,\, = \frac{1}{5} \times 20 = 4V

P.D. across AN = 4 + 4 = 8 V

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