The reagent to convert 2-phenyl propanamide into 1-phenyl ethanamine is?

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${Br}_{2} / NaOH$

Excess $H_{2}$

Red/P

${LiAlH}_{4}$ in ether

answer is B.

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Detailed Solution

Hoffmann bromamide reaction is when an amide is treated with bromine in a liquid or ethanolic arrangement of sodium hydroxide, degradation of amide happens prompting the development of $1 °$ amine. This reaction includes the degradation of amide and is prevalently known as the Hoffmann bromamide degradation reaction. This happens due to the intramolecular shifting of the alkyl group.

Hence, the correct answer is option B) ${Br}_{2} / NaOH$ .

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