The reagent used in Stephen’s reaction is

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$S n C l_{2} + H C l$

$L i A l H_{4} / H_{2} O$

$H_{2} / P d - B a S O_{4}$

Zn + HCl

answer is D.

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Detailed Solution

In this reaction, the reagent that is used is stannous chloride in the presence of hydrochloric acid. These reagents reduce the carbon atom that is present in the nitrile group and converts into aldehydic group.

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