The reagent ‘X’ is:
${CH}_{3} {CH}_{2} {CH}_{2} OH \overset{x}{⟶} {CH}_{3} CH = {CH}_{2}$

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$5 % H_{2} {SO}_{4} at 50^{0} C$

$95 % H_{2} {SO}_{4} at 170^{\circ} C$

$A_{2} O_{3}, 170^{\circ} C$

$75 % H_{2} {SO}_{4} at 100^{\circ} C$

answer is C.

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Detailed Solution

Sulphuric acid is highly hygroscopic in nature. When alcohol reacts with concentrated sulphuric acid, then alcohol undergoes dehydration and forms alkene as a major product.

Hence, option-C is correct.

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