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The reagent(s) that can selectively precipitate $S^{2 -}$ from a mixture of $S^{2 -}$ and ${SO}_{4}^{2 -}$ in an aqueous solution is (are) :

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${CuCl}_{2}$

${BaCl}_{2}$

$Pb {({OOCCH}_{3})}_{2}$

${Na}_{2} [Fe (CN)_{5} NO]$

answer is A, C.

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Detailed Solution

The forms of CuCl₂ are Cu²⁺ and Cl^-1.

CuSO₄ is now quite soluble in water, whereas $CuS$ turns into a dark ppt.

Pb²⁺ becomes lead sulfide and lead sulfate when it interacts with S^2- and ${SO}_{4}^{2 -}$ .

Lead sulfate is more soluble. It produces ppt.

So, options A and C are correct.

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