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Q.

The real part of a z that satisfies iz4+1=0 is

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a

sinπ4

b

cosπ8

c

0

d

-1

answer is B.

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Detailed Solution

iz4=-1iz4=i2 ⇒ z4=iz4=cosπ2+i sinπ2z=cosπ2+i sinπ21/4z=cosπ8+i sinπ8 ⇒ Re(z)=cosπ8

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