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The real $x$ for which $15 x^{2} + 16 x - 15 < 0$ is

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$- \frac{5}{3} < x < \frac{3}{5}$

$\frac{5}{3} < x < \frac{- 3}{5}$

$\frac{3}{5} < x < \frac{5}{3}$

$- \frac{5}{3} < x < \frac{- 3}{5}$

answer is A.

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Detailed Solution

$15 x^{2} + 16 x - 15 < 0$

$15 x^{2} + 25 x - 9 x - 15 < 0$

$5 x (3 x + 5) - 3 (3 x + 5) < 0$

$(5 x - 3) (3 x + 5) < 0$

$\frac{- 5}{3} < x < \frac{3}{5}$

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