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The rear side of truck is open and a box of mass 50kg is placed at 3.2m away from the open end. The co-efficient of friction between the box and the surface is 0.2. If the truck starts from rest and moves on a straight road with acceleration $2 . {4ms}^{- 2}$ the box falls off the truck after a time $(g = 10 m s^{- 2})$

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$50 \frac{8}{\sqrt{41}} s$

4 s

8 s

$\sqrt{8} s$

answer is B.

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Detailed Solution

$a^{1} = a - μ_{k} g$

$S = \frac{1}{2} a^{1} t^{2} \Rightarrow t^{2} = \frac{2 s}{a^{1}}$

$t = \sqrt{\frac{2 \times 3.2}{2.4 - 0.2 \times 10}} = \sqrt{16} = 4 \sec$

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