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The rear side of a truck is open and a box of 40 kg mass is placed 5 m away from the open end as shown in figure. The coefficient of friction between the box the surface below it is 0.15. On a straight road, the truck starts from rest and accelerates with 2 ms^-2 . At what distance from the starting point does the box fall from the truck? (Ignore the size of the box.)

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20m

10m

$\sqrt{20} m$

answer is A.

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Detailed Solution

$a_{b} = a - μg = 2 - 1.5 = 0.5 {ms}^{- 2}$

$t = \sqrt{\frac{2 l}{a_{b}}} = \sqrt{\frac{2 \times 5}{0.5}} = \sqrt{20} s$

$s = \frac{1}{2} {at}^{2} = \frac{1}{2} \times 2 \times 20 = 20 m$

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