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The rear side of truck is open and a box of mass 50kg is placed at 3.2m away from the open end. The co-efficient of friction between the box and the surface is 0.2. If the truck starts from rest and moves on a straight road with acceleration $2.1 {ms}^{- 2}$ the box falls off the truck after a time $(g = 10 {ms}^{- 2})$

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8 s

4 s

\sqrt{8} s

\frac{8}{\sqrt{41}} s

answer is C.

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Detailed Solution

$F - f = ma$

$50 \times 2 .1 - 0.2 \times 50 \times 10 = 50 a$

$a = 0 {ms}^{- 2}$

$S = \frac{1}{2} {at}^{2}$

$3.2 = \frac{1}{2} \times 0.1 \times t^{2}$

$t^{2} = 64$

$t = 8 s$

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