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The reduction electrode potential E, of 0.1M solution of M⁺ ions ( $E_{RP}^{°}$ = - 2.36 V) is:

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None of these

-2.41

-4.82

+2.411

answer is A.

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Detailed Solution

$\begin{array}{l} E = E_{RP}^{\circ} + \frac{0 .059}{1} \log 0 .1 \\ = - 2 .36 + 0 .059 \times (- 1) = - 2 .41 V \end{array}$

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