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The reduction electrode potential of chlorine electrode is maximum when the concentration of chloride ions in the solution at 1 bar pressure is

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$1 M$

$10^{- 2} M$

$10^{- 3} M$

$10^{- 4} M$

answer is A.

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Detailed Solution

$C {l_{2}}_{(g)} + 2 e^{-} ⇄ 2 C l^{-}$

$E_{R . P} = E_{R . P .}^{0} - \frac{0.059}{2} \log {[C l^{-}]}^{2}$

$= E_{R . P .}^{0} - 0.059 \log [C l^{-}]$

At the lowest conc. of Cl^- ie.e 10^-4 we get high value of E_R.P

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