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Q.

The reduction potential (E0, in V) of  MnO4−(aq)/Mn(s) is ______.
[Given:EMnO4(aq)/MnO2(s)0=1.68V;EMnO2(s)/Mn2+(aq)0=1.21V;EMn2+(aq)/Mn(s)0=1.03V]

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answer is 0.77.

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Detailed Solution

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1MnO4(aq)+4H++3eMnO2(s)+2H2O; E=1.68VΔG10=3F(1.68)=5.04F
2MnO2(s)+4H++2eMn2++2H2O; E=1.21VΔG20=2F(1.21)=2.42F
3Mn2+(aq)+2eMn(s);    E=1.03VΔG30=2F(1.03)=+2.06F
Adding (1), (2) and (3),
MnO4(aq)+8H++7eMn(s)+4H2OΔG=ΔG10+ΔG20+ΔG30 =(5.042.42+2.06)F7FE=5.4F E=0.77V

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