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The reduction potential of hydrogen electrode will be positive if

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$p (H_{2}) = 1 atm, [H^{+}] = 1 M$

$p (H_{2}) = 2.5 atm, [H^{+}] = 1.5 M$

$p (H_{2}) = 2 atm, [H^{+}] = 1 M$

$p (H_{2}) = 1 atm, [H^{+}] = 2 M$

answer is B.

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Detailed Solution

$E_{H^{+} |H_{2}| Pt} = - \frac{R T}{F} \ln \frac{p_{H_{2}}^{l / 2}}{[H^{+}]}$

The combination $p (H_{2}) = 1 atm$ and $[H^{+}] = 2 M$ will make $E_{H^{+} |H_{2}| Pt}$ positive..

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