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The reduction potential of hydrogen half-cell will be negative if

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p(H₂) = 2 atm and [H⁺] = 2.0 M

p(H₂) = 2 atm and [H⁺] = 1.0 M

p(H₂) = 1 atm and [H⁺] = 2.0 M

p(H₂) = 1 atm and [H⁺] = 1.0 M

answer is B.

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Detailed Solution

$\begin{array}{l} Pt |H_{2} (g)| H^{+} (aq) \\ H^{+} + e^{-} ⟶ 1 / 2 H_{2} (g) \\ E = E^{\circ} - \frac{0.059}{1} \log \frac{{(P_{H_{2}})}^{1 / 2}}{[H^{+}]}; E = 0 - \frac{0.059}{1} \log \frac{2^{1 / 2}}{1} = - ve . \end{array}$

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