The reduction step in the Calvin cycle utilizes A molecules of ATP for phosphorylation and B of NADPH for reduction per $C{O}_2$  molecule fixed.

	A	B
1	2	2
2	3	3
3	2	3
4	3	2

Reduction – These are a series of reactions that lead to the formation of glucose. The steps involve utilization of 2 molecules of ATP for phosphorylation and two of NADPH for reduction per CO2 molecule fixed. The fixation of six molecules of CO2 and 6 turns of the cycle are required for the removal of one molecule of glucose from the pathway.