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Q.

The refracting angle of a prism is ‘A’ and the refractive index of the material of the prism is cot⁡A2. The angle of minimum deviation in the prism is

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a

A

b

90 - A

c

180 - 2A

d

180 - A

answer is C.

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Detailed Solution

μ=sin⁡A+D2sin⁡A2 Cot⁡A2=sin⁡A+D2sin⁡A2Cos⁡A2=sin⁡A+D2sin⁡90+A2=sin⁡A+D290+A2=A+D2⇒D=180−2A

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