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Q.

The refractive angle of a prism is A, and the refractive index of the material of the prism is cot $(A / 2)$ .The angle of minimum deviation is

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a

$180 ° - 3 A$

b

$180 ° + 2 A$

c

$90 ° - A$

d

$180 ° - 2 A$

answer is D.

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Detailed Solution

$μ = \frac{\sin (\frac{A + δ_{m}}{2})}{\sin (A / 2)}$

Given, $μ = \cot (\frac{A}{2})$
Solving, we get $\sin = 180 ° - 2 A$

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