The refractive index of a certain glass is 1.5 for light whose wavelength in vacuum is $6000 A^{\circ}$ . The wavelength of this light when it passes through glass is

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$9000 A^{\circ}$

$15000 A^{\circ}$

$6000 A^{\circ}$

$4000 A^{\circ}$

answer is A.

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Detailed Solution

From

$\begin{array}{l} μ_{1} λ_{1} = μ_{2} λ_{2} \\ \Rightarrow μ_{m} λ_{m} = μ_{a} λ_{a} \\ λ_{m} = \frac{λ_{a}}{μ_{m}} = \frac{6000}{1.5} = 4000 A^{\circ} \end{array}$

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