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The refractive index of a material of a plano concave lens is 5/3, the radius of curvature is 0.3 m. The focal length of the lens in air is

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–0.6m

–0.45m

–0.75m

–1.0m

answer is A.

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Detailed Solution

$\frac{1}{f} = (μ - 1) (- \frac{1}{R})$

$μ = \frac{5}{3}, R = 0.3 m$

$\frac{1}{f} = \frac{2}{3} (\frac{- 1}{0.3}); f = - \frac{0.9}{2}; f = - 0.45 m$

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