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Q.

The refractive index of the material of a double convex lens is 1.5 and its focal length is 5cm.If the radii of curvature are equal, the value of the radius of curvature (in cms) is

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a

9.5

b

6.5

c

8.0

d

5.0

answer is A.

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Detailed Solution

$R_{1} = R, R_{2} = - R, μ = 1.5 f = 5 cm$ $\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

$\frac{1}{5} = (1.5 - 1) (\frac{2}{R})$

$\frac{1}{5} = \frac{1}{2} \times \frac{2}{R}$

$R = 5 cm$

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