The refractive indices of glycerine and diamond with respect to air are 1.4 and 2.4 respectively. Calculate the speed of light in glycerine and diamond. From these results, also calculate the refractive index of diamond with respect to glycerine. (c = 3 × 10⁸ m/s)

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2.143 × 10⁸ m/s; 1.250 × 10⁸ m/s; 1.714

1.143 × 10⁸ m/s; 1.250 × 10⁸ m/s; 1.714

2.143 × 10⁸ m/s; 2.250 × 10⁸ m/s; 1.714

2.143 × 10⁸ m/s; 1.250 × 10⁸ m/s; 1.514

answer is A.

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Detailed Solution

$Velocity in glycerine = \frac{3 x 10^{8}}{1.4} = 2.143 x 10^{8} m / s Velocity in diamond = \frac{3 x 10^{8}}{2.4} = 1.25 x 10^{8} m / s R . I of Diamond w . r . t glycerine = \frac{R . I of diamond}{R . I of glycerine} = \frac{2.4}{1.4} = 1.714$

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