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Q.

The relation between µ and H for a specimen of iron is μ=0.4H+12×10−4 henry/metre. The value of H which produces flux density of 1 tesla will be

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a

250 A/m

b

750 A/m

c

103 A/m

d

500 A/m

answer is B.

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Detailed Solution

B=μH=0.4H+12×10−4H

⇒1=0.4+12×10-4H

⇒H=0.612×10-4=500 A/m

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