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The relation between magnetic moment $μ$ of a revolving electron around the nucleus with principal quantum number n is

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$μ \propto \frac{1}{n^{3}}$

$μ \propto \frac{1}{n^{2}}$

$μ \propto n^{2}$

$μ \propto n$

answer is A.

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Detailed Solution

$Magnetic moment = μ = iA$

$μ = \frac{e}{T} {πr}^{2}$

$μ = \frac{ev}{2 πr} {πr}^{2} = \frac{evr}{2}$

$but mvr = \frac{nh}{2 π}$

$vr = \frac{nh}{2 πm}$

$μ = \frac{e}{2} \frac{nh}{2 πm} μ \propto n$

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