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Q.

The relation between standard reduction potential of a cell and equilibrium constant is shown by

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a

$E_{cell}^{o} = \frac{{logK}_{c}}{n}$

b

$E_{c e l l}^{o} = \frac{n}{0.059} \log K_{c}$

c

$E_{cell}^{o} = \frac{0.059}{n} {logK}_{c}$

d

$E_{cell}^{o} = 0.059 {nlogK}_{c}$

answer is B.

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Detailed Solution

$E_{c e l l}^{o} = \frac{0.059}{n} \log K_{c}$

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