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Q.

The relation between the escape velocity $v_{e}$ in the orbit and orbital velocity $v_{o}$ is given by

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a

$\sqrt{V_{e}} = 2 V_{o}$

b

$V_{e} = V_{o}$

c

$V_{e} = \sqrt{2} V_{o}$

d

$V_{o} = \sqrt{2} V_{e}$

answer is A.

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Detailed Solution

$V_{e} = \sqrt{\frac{2 G M}{r}} a n d V_{o} = \sqrt{\frac{G M}{r}} ∴ V_{e} = \sqrt{2} V_{o}$

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