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Q.

The relation between the orbital radius and the electron velocity for a dynamically stable orbit in a hydrogen atom is: (where, all notations have their usual meanings)

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a

v=4πε0me2r

b

r=e24πε0v

c

v=e24πε0mr

d

3r=ve24πε0m

answer is C.

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Detailed Solution

In hydrogen atom electrostatic force of attraction Fe between the revolving electrons and the nucleus provides the requisite centripetal force Fc to keep them in their orbits. 

Thus, 

  Fe=Fc         mv2r=14πε0e2r2

  v2=e24πε0mr v=e24πε0mr

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