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Q.

The relation between U, P and V for an ideal gas in an adiabatic process is given by relation U = a + bPV. Find the value of adiabatic exponent (γ) of this gas 

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a

aa+b

b

a+1b

c

b+1b

d

b+1a

answer is A.

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Detailed Solution

(1) U=a+bPV   ......(1) 

In adiabatic change, dU=-dW=nRγ-1T2-T1=nRγ-1dT U=dU=nRγ-1dT or U=nRγ-1T+a=PVγ-1+a  .....(2)

where a is the constant of integration. Comparing (1) and (2), we get 

b=1γ-1γ=b+1b

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