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Q.

The relation $3 t = \sqrt{3 x} + 6$ describes the displacement of a particle in one direction where x is in meters and t in sec. The displacement, when velocity is zero, is (in m)

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Detailed Solution

$\sqrt{3 x} = 3 t - 6 \Rightarrow 3 x = {(3 t - 6)}^{2} Differentiating wrt time, \Rightarrow 3 v = 2 (3 t - 6) \times 3 \Rightarrow v = 6 t - 12$

Velocity is zero When t = 2sec.
$∴ x = 0 m$

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