The relationship between angle of incidence i, prism of angle A and angle of minimum deviation for a triangular prism is

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$2 A + δ_{m} = i$

$A + δ_{m} = 2 i$

$A + δ_{m} = i$

$A + δ_{m} / 2 = i$

answer is B.

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Detailed Solution

For refraction through prism,
$i_{1} + i_{2} = δ + A and r_{1} + r_{2} = A$
For minimum deviation,
$\begin{array}{l} i_{1} = i_{2} = i and r_{1} = r_{2} = r \\ S o \\ A + δ_{m} = 2 i \end{array}$

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