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Q.

The relationship between energy E, of the radiation with a wavelength $8000 Å$ and the energy of the radiation with a wavelength $16000 Å$ is

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a

$E_{1} = 2 E_{2}$

b

$E_{1} = 4 E_{2}$

c

$E_{1} = 6 E_{2}$

d

$E_{1} = E_{2}$

answer is A.

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Detailed Solution

$\frac{E_{1}}{E_{2}} = \frac{λ_{2}}{λ_{1}} = \frac{16000}{8000} = 2$

$∴ E_{1} = 2 E_{2}$

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