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Q.

The relative lowering of vapor pressure of 0.2 molal solution in which the solvent is Benzene is

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a

$15.6 \times 10^{- 1}$

b

$15.6 \times 10^{- 3}$

c

0.05

d

$15.6 \times 10^{- 4}$

answer is B.

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Detailed Solution

$\frac{P^{o} - P}{P^{o}} = \frac{W_{A}}{W_{A}} \times \frac{M_{B}}{W_{B}}$

$\Rightarrow Molality (m) = \frac{w_{A}}{m_{A}} \times \frac{1000}{W_{B}}$

$\Rightarrow \frac{w_{A}}{m_{A}} \times \frac{1}{W_{B}} = \frac{m}{1000}$

$\frac{P^{o} - P}{P^{o}} = \frac{m}{1000} \times M$

$\frac{0.2 \times 78}{1000}$

$= 15.6 \times 10^{- 3}$

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