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Q.

The relative lowering of vapor pressure of 0.2 molal solution in which the solvent is Benzene is

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a

15.6×10-1

b

15.6×10-3

c

0.05

d

15.6×10-4

answer is B.

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Detailed Solution

 Po-PPo=WAWA×MBWB

⇒Molality (m)=wAmA×1000WB

⇒wAmA×1WB=m1000

Po-PPo=m1000×M

0.2×781000

=15.6×10-3

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