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The relative lowering of vapour pressure of 0.2 molal solution in which the solvent is Benzene is

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$15.6 \times 10^{- 4}$

$15.6 \times 10^{- 3}$

$15.6 \times 10^{- 1}$

0.05

answer is B.

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Detailed Solution

$\frac{P ° - P}{P °} = m \times \frac{M}{1000} = 0.2 \times \frac{76}{1000} = 15.6 \times 10^{- 3}$

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