The relative order of acidity of alcohols in comparison to $H_{2} O$ and $HC \equiv CH$ is

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$H_{2} O > ROH > HC \equiv CH$

$H_{2} O > HC \equiv CH > ROH$

$ROH > HCOOH > H_{2} O$

$ROH > H_{2} O > HC \equiv CH$

answer is A.

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Detailed Solution

The relative order of acidity is $H_{2} O > ROH > HC \equiv CH$ .

alcohols are relatively weak Bronsted acids. Proton transfer is the most crucial reaction to take into account with nucleophiles since the hydroxyl proton is the most electrophilic site.

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