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Q.

The remainder when x9999+x8888+x7777+.......+x1111+1 is divided by x9+x8+x7+.......+x1+1  is

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a

P(x)Q(x)=(x1)s(x)g(x)

b

P(x).Q(x)=(x1)s(x)g(x)

c

P(x)Q(x)=(x+1)s(x)g(x)

d

P(x)÷Q(x)=(x1)s(x)g(x)

answer is A.

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Detailed Solution

P(x)=x9999+x8888+x7777+.......+x1111+1Q(x)=x9+x8+x7+.......+x1+1P(x)Q(x)=(x9999x9)+(x8888x8)+......+(x1111x1)x9(x99901)+x8(x88801)+......+x(x11101)x9(x101)Q1(x)+x8(x101)Q2(x)+.......+x10(x101)Q0(x)=(x101)(x9Q1(x)+.....+1)=(x1)s(x)g(x)(x1)is a factor off(x)P(x)Q(x)=(x1)s(x)g(x)

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The remainder when x9999+x8888+x7777+.......+x1111+1 is divided by x9+x8+x7+.......+x1+1  is