The resistance in a burner of an electric stove are connected together in an arrangement shown in figure. This arrangement is connected to the supply mains at point 1 and 2, after a certain time, 5kg of water is heated to the boiling point. How much water (in kg) can be heated to the boiling point in the same time interval when the arrangement of resistance is connected to the supply mains at point 1 and 3? The initial temperature of the water is the same in both cases. Neglect all heat losses.

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answer is 8.

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Detailed Solution

$\frac{V^{2}}{R} t = 5 \times S \times (100 - T) \frac{8 V^{2}}{5 R} \times t = m \times S \times (100 - T) m = 8 kg$

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