Q.

The resistance of 0.1 M weak acid HA in a conductivity cell is  2×103 Ohm. The cell constant of the cell is 0.78 Cm1 and  λm  of acid HA is  390 S cm2mole1. The pH of the solution is

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a

4.2

b

3.3

c

3

d

5

answer is D.

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Detailed Solution

Given,C=0.1M

Λm=390Scm2mol1

R=2×103ohm

G=0.78cm1

Now, K=RG=0.782×103=3.9×104

Λm=K×1000C=3.9×104×10000.1=3.9

α=ΛmΛm=3.9390=102

[H+]=Cα=0.1×102=103

So, pH=log103=3

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