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Q.

The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of 0.88cm^–1. The value of equivalent conductance of solution is –

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a

425 mho cm² g eq^–1

b

400 mho cm² g eq^–1

c

295 mho cm² g eq^–1

d

419 mho cm² g eq^–1

answer is A.

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Detailed Solution

$\land_{e q} = κ \times \frac{1000}{N} = \frac{1}{R} \times \frac{l}{a} \times \frac{1000}{N}$

$\frac{1}{R} \times c e l l constant \times \frac{1000}{N} = \frac{1}{220} \times 0.88 \times \frac{1000}{0.01}$

400 mho cm² g eq^–1

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The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of 0.88cm–1. The value of equivalent conductance of solution is –