The resistance of a bulb filament is 100 $Ω$ at a temperature of 100°C. If its temperature coefficient of resistance be 0.005 per°C, its resistance will become 200 $Ω$ at a temperature of

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200°C

500°C

400°C

300°C

answer is B.

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Detailed Solution

$\begin{array}{l} α = \frac{R_{2} - R_{1}}{R_{1} t_{2} - R_{2} t_{1}}; 5 \times 10^{- 3} = \frac{200 - 100}{100 \times t_{2} - 200 \times 100} \\ t_{2} = 400^{\circ} C \end{array}$

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