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Q.

The resistance of a bulb filament is 100Ω at a temperature of 100°C. If its temperature coefficient of resistance be 0.005 per°C, its resistance will become 200Ω at a temperature of

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a

200°C

b

500°C

c

400°C

d

300°C

answer is B.

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Detailed Solution

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α=R2−R1R1t2−R2t1;5×10−3=200−100100×t2−200×100t2=400∘C

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