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The resistance of a heater coil is 110 ohm. A resistance R is connected in parallel with it and the combination is joined in series with a resistance of 11ohm to a 220 volt main line. The heater operates with a power of 110 watts. The value of R in ohm is

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12.22

24.42

negative

given values are not correct.

answer is A.

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Detailed Solution

Power consumed by heater is 110 W .

so, by using $P = \frac{V^{2}}{R}; V_{h} = 110 V o l t$

$\Rightarrow V_{R} = 110 V$

$i_{11 o h m} = \frac{220 - 110}{11} = 10 A$

$i_{h} = \sqrt{\frac{110}{110}} = 1 A$

$\Rightarrow i_{R} = 10 - 1 = 9 A$

Applying Ohms law for resistance R,

$V = i R \Rightarrow R = 12.22 Ω$

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