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The resistance of a metal wire is given by R=V/ I where v is the potential difference and I is the current. In a circuit, the potential difference across resistance is/ where v is the potential difference and I is $V = (8 \pm 0 \cdot 5)$ volt and current in circuit $I = (4 \pm 0 \cdot 2)$ amp. what is the value of resistance with its percentage error?

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$(2 \pm 0 \cdot 7 %) ohm$

$(2 \pm 3 \cdot 5 %) ohm$

$(2 \pm 11 \cdot 25 %) ohm$

$(2 \pm 5 \cdot 6 %) ohm$

answer is C.

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Detailed Solution

$R = V / I$
Or $\frac{Δ R}{R} = \frac{Δ V}{V} + \frac{Δ I}{I}$
Or $\frac{ΔR}{R} = (\frac{0 \cdot 5}{8} + \frac{0 \cdot 2}{4}) 100 % = 11 \cdot 25 %$

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