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Q.

 The resistance of a thin silver wire is (1.0Ω at 20°C). The wire is placed in a liquid bath and its resistance rises to 1.2Ω. What is the temperature of the bath? α for silver is 3.8×10-3/C  ∘.

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a

T=72.6°C

b

T=89.6°C

c

T=49.6°C

d

T=116.6°C

answer is C.

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Detailed Solution

R(T)=R01+αT-T0

Here, R(T)=1.2Ω,  R0=1.0Ω,  α=3.8×10-3/C  ∘ and T0=20°C

Substituting the values, we have 1.2=1.01+3.8×10-3(T-20)

or

3.8×10-3(T-20)=0.2

Solving this, we get

T=72.6°C

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