The resistance of all the wires between any two adjacent dots is R. The equivalent resistance between A and B as shown in figure is

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$\frac{7}{6} R$

none of these

$\frac{14}{8} R$

$\frac{7}{3} R$

answer is B.

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Detailed Solution

No current will pass through the wire between CD due to balanced condition of Wheatstone bridge.

$\begin{aligned} R_{AB} = \frac{\frac{7 R}{3} \times \frac{7 R}{3}}{\frac{7 R}{3} + \frac{7 R}{3}} = \frac{\frac{7 R}{3} \times \frac{7 R}{3}}{2 \times \frac{7 R}{3}} = \frac{7 R}{6} \end{aligned}$

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