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Q.

The resistance of conductivity cell containing 0.01 M KCl solution at 298 K is 1750 Ω. If the
conductively of 0.01 M KCl solution at 298 K is 0.152×10-3 S cm-1, then the cell constant of the conductivity cell is______________ ×10-3 cm-1

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answer is 266.

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Detailed Solution

K=1R× cell constant         

0.152×10-3=11750 cell constant 

 cell constant = 266×10-3

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The resistance of conductivity cell containing 0.01 M KCl solution at 298 K is 1750 Ω. If theconductively of 0.01 M KCl solution at 298 K is 0.152×10-3 S cm-1, then the cell constant of the conductivity cell is______________ ×10-3 cm-1