The resistance of N /10 solution is found to be 2.5×103Ω. The equivalent conductance of the solution is (cell constant =1.25cm−1

5 ohm − 1 ⋅ cm 2 ⋅ eq − 1

5 ohm − 1 ⋅ cm 2 ⋅ eq − 1

2.5 ohm − 1 ⋅ cm 2 ⋅ eq − 1

1.25 ohm − 1 ⋅ cm 2 ⋅ eq − 1

2 ohm − 1 ⋅ cm 2 ⋅ eq − 1

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The resistance of N /10 solution is found to be $2.5 \times 10^{3} Ω .$ The equivalent conductance of the solution is (cell constant $= 1.25 {cm}^{- 1})$

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$5 {ohm}^{- 1} \cdot {cm}^{2} \cdot {eq}^{- 1}$

$2.5 {ohm}^{- 1} \cdot {cm}^{2} \cdot {eq}^{- 1}$

$1.25 {ohm}^{- 1} \cdot {cm}^{2} \cdot {eq}^{- 1}$

$2 {ohm}^{- 1} \cdot {cm}^{2} \cdot {eq}^{- 1}$

answer is A.

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$Λ_{eq} = \frac{K \times 1000}{N} = \frac{\frac{1}{R} \times G^{*} \times 1000}{N}$

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