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The resistance of wire PQ is $410 Ω$ . Which is tapped with the external wire as shown in the figure. The value of R is not known. If the potential difference between AB is 400 volts and the net current through the source battery is 6 ampere, then which of the following is/are correct.

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The current in $25 Ω$ resistor is $\frac{2}{5}$ ampere

The potential, drop across 120 $Ω$ resistor is 60 volts

The resistance of unknown resistor R is $200 Ω$

The equivalent resistance across AB is $\frac{200}{3} Ω$

answer is A, B, C, D.

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Detailed Solution

Equivalent resistance between P and Q = $100 Ω$
So current towards $P = \frac{400}{100} = 4$ amphere
So, $R = \frac{400}{2} = 200 Ω$
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